5x-x^2+1=0

Solution for 5x-x^2+1=0 equation:

5x-x^2+1=0

We add all the numbers together, and all the variables

-1x^2+5x+1=0

a = -1; b = 5; c = +1;
Δ = b2-4ac
Δ = 52-4·(-1)·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{29}}{2*-1}=\frac{-5-\sqrt{29}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{29}}{2*-1}=\frac{-5+\sqrt{29}}{-2}
$